A silver bar 0.125 meter long is subjected to a temperature change from 200 C to 100 C. What will be the length of the bar after the temp change?
A:0.124764 meter
B:0.00023635 meter
C: 0.00002363 meter
D:0.0000189 meter
deltal=L*alpha*deltaTemp
Now you know it will be small. Subtract it from .125.
So only one answer is possible of the choices. You don't need to do any calculations.
A:0.124764 meter
To determine the length of the silver bar after the temperature change, we can use the coefficient of linear expansion. The linear expansion formula is given by:
ΔL = α * L0 * ΔT
Where:
ΔL is the change in length
α is the coefficient of linear expansion
L0 is the initial length of the bar
ΔT is the change in temperature
In this case, we need to find ΔL, so we rearrange the formula as follows:
ΔL = α * L0 * ΔT
Given:
L0 = 0.125 meters (initial length)
ΔT = 100°C - 200°C = -100°C (change in temperature)
The coefficient of linear expansion for silver is typically α = 0.0000189 (per degree Celsius).
Substituting the values into the formula:
ΔL = 0.0000189 * 0.125 * -100 = -0.00023775 meters
Since ΔL represents the change in length, we can find the final length by adding ΔL to the initial length:
Final length = L0 + ΔL = 0.125 + (-0.00023775) = 0.12476225 meters
Rounding off to the nearest 6 decimal places, the final length is approximately 0.124764 meters.
Therefore, the correct option is A: 0.124764 meter.