A mole of HBr, a strong acid, is made up to a liter of solution with pure water. At equilibrium...

(a) [H+] = 1M
(b) [H+] = 0M
(c) pH = 0
(d) both a & c
(e) we cannot say without exact pKa of hydrobromic acid.

So you have (HBr) = 1 mole/L = 1M

Since HBr is a strong acid, (H^+) must be 1 M also.

Thank you!!

To determine the answer to this question, we need to consider the dissociation behavior of the hydrobromic acid (HBr) in water. HBr is a strong acid, which means it completely dissociates into hydrogen ions (H+) and bromide ions (Br-) when in an aqueous solution.

When a mole of HBr is made up to a liter of solution with pure water, it means that one mole of HBr is dissolved in a liter of water. As a strong acid, it will completely ionize into H+ and Br- ions.

At equilibrium, the concentration of H+ ions in the solution is equal to the concentration of the original HBr. Since one mole of HBr is made up to a liter of solution, the concentration of H+ ions is 1M.

Therefore, the correct answer is (a) [H+] = 1M.