According to the experiment procedure, given that the NaOH solution has a concentration of 0.100M, and that the vinegar (acetic acid) has a concentration of 5.0% m/m (mass percent), what volume (mL) of titrant would be required to reach the “equivalence point” if you place 2.500g of vinegar in the flask (show calculations)?

5% acetic acid is 5 g acid/100 g soln. Acid to titrate is 5g x (2.5/100) = 0.125 g acid. Convert to moles. moles = grams/molar mass.

Then moles acid = moles NaOH at the equivalence point.
moles NaOH = M x L. Solve for L and convert to mL.

To calculate the volume of titrant required, we need to determine the number of moles of acetic acid in the vinegar and then use the stoichiometry of the reaction between acetic acid and NaOH.

Here's how you can calculate it step by step:

Step 1: Convert the mass percent of acetic acid in vinegar to grams of acetic acid:
Mass percent = (mass of solute / mass of solution) * 100
Let's assume the mass of vinegar is equal to its mass of solution, so:
Mass percent = (mass of acetic acid / mass of vinegar) * 100
5.0 = (mass of acetic acid / 2.500) * 100

Rearranging the equation to find the mass of acetic acid:
mass of acetic acid = (5.0 / 100) * 2.500

Step 2: Convert the mass of acetic acid to moles using its molar mass:
The molar mass of acetic acid (CH3COOH) is 60.052 g/mol.
moles of acetic acid = mass of acetic acid / molar mass of acetic acid

Step 3: Determine the stoichiometry of the reaction:
From the balanced equation of the reaction between acetic acid and NaOH, we know that one mole of acetic acid reacts with one mole of NaOH.
The molar ratio is 1:1.

Step 4: Calculate the moles of NaOH required:
From the stoichiometry, we know that moles of acetic acid = moles of NaOH.

Step 5: Convert the moles of NaOH to volume using its concentration:
We know the concentration of NaOH is 0.100 M, which means 0.100 moles of NaOH are present in 1 liter (1000 mL) of the solution.
So, moles of NaOH = concentration of NaOH * volume of NaOH (in liters)

We can rearrange the equation to find the volume of NaOH:
volume of NaOH (in liters) = moles of NaOH / concentration of NaOH

Step 6: Convert the volume of NaOH from liters to milliliters:
Since we need to find the volume in mL, we can multiply the volume in liters by 1000.

Now, let's put it all together and calculate the volume of titrant required:

mass of acetic acid = (5.0 / 100) * 2.500
moles of acetic acid = mass of acetic acid / molar mass of acetic acid
moles of NaOH = moles of acetic acid
volume of NaOH (in liters) = moles of NaOH / concentration of NaOH
volume of titrant (in mL) = volume of NaOH * 1000

I hope this explanation helps you understand the process to calculate the volume of titrant required in the given experiment.