I would appeciate any help with identifying the chiral carbons, if any, in each of the following compounds:
OCH3
2. CH3--CH--CH3
OH O
11. CH3--CH--C--CH3
OH
12. CH3--C--CH3
OH
CH3 O
15.CH3--CH--C--CH3
Br
CH3--C--CH2--CH3
OH
thank you.
There is no way anyone can know what you have typed. As I pointed out in an earlier response, the board ignores any space after the first one you make; take a look at your post and you can see there is no way of knowing where the groups are attached that you have typed above and below the line. A a carbon to be chiral, it must have four different groups attached. That's easy enough to count without posting a question. An alternative is to try writing the condensed structure.
Ah, I see what you are talking about.
OCH3 is above the CH
________________________
OH O is above the CH
Also OH is under the CH
________________________
OH is under the C
___________________
CH3 O is above the CH
____________________
Br is above the C
OH is under the C
_____________________________________
any help is appreciated. If it is four groups, then wouldn't all be chiral carbons?
#2 has no chiral center. Why? On the central C, there is an H, an OCH3, and TWO CH3 groups; therefore, it doesn't have four separate groups.
#11. I can't figure out from your description. I think the OH under the ring probably goes on the C and not the CH.
#12.No chiral center for the same reason as #2.
15. Some of the C atoms don't have four bonds. If you meant
CH3CH(OCH3)CH2CH3 (I have added H atoms to the #2 C atom from the right side), that C is chiral. It has a CH3, H, OCH3, and CH2CH3 which makes four different groups attached.
last one is not numbered. It has a chiral center. There is a CH3, Br, OH, and CH2CH3; again four separate groups.
Hey, thanks a lot.
Yes, sorry I did write those incorrectly.Here they are:
11. CH3--CH--C--CH3
OH is above the CH
O is above the C
_________________________________
So 15. does have four separate groups?
15. CH3--CH--C--CH3
CH3 is above the CH
O is above the C
Try writing them in this fashion.
CH3-CH(OCH3)-CH3 [not chiral]
CH3-CH(OH)-C(=O)-CH3 [chiral]
CH3-C(OH)2-CH3 [not chiral]
CH3-CH(CH3)-C(=O)-CH3 [not chiral]
CH3-C(Br)(OH)-CH2-CH3 [chiral]
To identify chiral carbons in a molecule, you need to examine the carbon atoms and determine if each carbon atom is bonded to four different groups. If a carbon atom meets this criterion, it is chiral. Here's how to identify the chiral carbons in each of the given compounds:
1. OCH3: There is only one carbon atom present, and it is bonded to three hydrogen atoms and an oxygen atom. Since it does not have four different groups bonded to it, it is not chiral.
2. CH3--CH--CH3: In this case, the central carbon atom is bonded to two other carbon atoms and two hydrogen atoms. Since all four groups bonded to it are the same, it is not chiral.
11. CH3--CH--C--CH3: The central carbon atom is bonded to a hydrogen atom, a methyl group (CH3), a hydroxyl group (OH), and another methyl group (CH3). Since it has four different groups bonded to it, it is chiral.
12. CH3--C--CH3: In this compound, the central carbon atom is bonded to two methyl groups (CH3) and a hydrogen atom. Since it does not have four different groups bonded to it, it is not chiral.
15. CH3--CH--C--CH3: The central carbon atom is bonded to three different groups: two methyl groups (CH3) and an oxygen atom. However, it is not chiral because it lacks a fourth different group.
Br
CH3--C--CH2--CH3
OH: In this case, the central carbon atom is bonded to a hydrogen atom, a methyl group (CH3), a bromine atom (Br), and a hydroxyl group (OH). Since it has four different groups bonded to it, it is chiral.
In summary, the chiral carbons are present only in compounds numbered 11 and 15.