# Algebra I

1. A Passenger train's speed is 60mi/h and a freight train's speed is 40mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip?

2. Lois rode her bike to visit a friend. She traveled at 10 mi/h. While she was there it began to rain. Her friend drove her home in a car traveling at 20 mi/h. Lois took 1.5 h longer to go to her friend's than to return home. How many hours did it take Lois to ride to her friend's house?

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1. distance = rate x time
passenger train rate = 60 mi/hr
freight train rate = 40 mi/hr.
distance traveled by P = 60*t
distance traveled by F = 40*t
time for F is 1.5 hours longer than P so
F dist = 40(t+1.5) = P dist = 60*t
set distance = to each other
60*t=40(t+1.5)
solve for t = time for passenger train.
Then t+1.5 = tiome for freight train.

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2. #2 is done the same say as #1. Post your work if you get stuck.

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3. 2:30

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4. 40(t+1.5)=60x t

2/3(t+1.5)= T

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