What formula do I use to figure how many mL of 6.00 M of HCl must be diluted to make 600 mL of a 0.500 M solution?

mL x M = mL x M

I posted this response by anonymous

To figure out how many mL of 6.00 M of HCl must be diluted to make 600 mL of a 0.500 M solution, you can use the formula for dilution:

M1V1 = M2V2

Let's break down the variables:
- M1 is the initial concentration of the solution you have (6.00 M of HCl).
- V1 is the initial volume of the solution you have (which is what we are trying to find).
- M2 is the final concentration you want to achieve (0.500 M).
- V2 is the final volume of the solution you want to make (600 mL).

Now, let's substitute the values into the formula:

(6.00 M) (V1) = (0.500 M) (600 mL)

To solve for V1, isolate it on one side of the equation:

V1 = (0.500 M) (600 mL) / (6.00 M)

Simplify the equation:

V1 = (0.500 M) (100 mL)

V1 = 50 mL

Therefore, to make a 0.500 M solution using 6.00 M HCl, you need to dilute 50 mL of the 6.00 M HCl to a final volume of 600 mL.