If 5.00 mL of HCl require 4.03 mL of 0.9581 M NaOH to just consume the HCl, what is the concentration of the HCl?
mL acid x M acid = mL base x M base
To find the concentration of the HCl solution, we can use the concept of stoichiometry, which relates the amount of one substance in a chemical reaction to another. In this case, we can use the balanced chemical equation for the reaction between HCl and NaOH:
HCl + NaOH -> NaCl + H2O
From the given information, we know that 5.00 mL of HCl solution reacts with 4.03 mL of 0.9581 M NaOH.
To calculate the concentration of HCl, we can set up the following equation using the concept of stoichiometry:
C1 * V1 = C2 * V2
Where:
C1 = concentration of NaOH in M (0.9581 M)
V1 = volume of NaOH in liters (4.03 mL converted to L)
C2 = concentration of HCl in M (unknown)
V2 = volume of HCl in liters (5.00 mL converted to L)
Rearranging the equation to solve for C2 (concentration of HCl):
C2 = (C1 * V1) / V2
Substituting the values into the equation:
C2 = (0.9581 M * 4.03 mL) / 5.00 mL
Now, let's calculate the concentration of HCl:
C2 = (0.9581 M * 0.00403 L) / 0.005 L
= 0.771 M
Therefore, the concentration of the HCl solution is approximately 0.771 M.
To find the concentration of HCl, we can use the concept of stoichiometry and the equation of the balanced chemical reaction between HCl and NaOH.
The balanced chemical equation for the reaction is:
HCl + NaOH → NaCl + H2O
From the given information, we can see that the stoichiometric ratio between HCl and NaOH is 1:1. This means that one mole of HCl reacts with one mole of NaOH.
Given volume of NaOH solution = 4.03 mL
Given molarity of NaOH solution = 0.9581 M
To find the number of moles of NaOH used, we can use the equation:
moles = volume (in liters) × molarity
The volume of NaOH solution in liters:
4.03 mL = 4.03 × 10^(-3) L
Using the given values, we can calculate the moles of NaOH:
moles of NaOH = (4.03 × 10^(-3) L) × (0.9581 mol/L)
Now, since the stoichiometric ratio is 1:1, the number of moles of HCl consumed will be the same as the number of moles of NaOH used.
Therefore, the moles of HCl consumed = moles of NaOH = (4.03 × 10^(-3) L) × (0.9581 mol/L)
Now, we have the moles of HCl consumed. However, we need to find the concentration of HCl in order to answer the question.
To find the concentration of HCl, we need to know the volume of HCl used and the moles of HCl consumed.
Given volume of HCl solution = 5.00 mL
Converting the volume of HCl to liters:
5.00 mL = 5.00 × 10^(-3) L
The concentration of HCl can be calculated using the equation:
concentration = moles/volume
Substituting the calculated values:
concentration of HCl = (4.03 × 10^(-3))/(5.00 × 10^(-3))
Thus, the concentration of the HCl solution is (4.03 × 10^(-3))/(5.00 × 10^(-3)) M.