Chemistry

What would the units of the rate constant k be in a second order equation if rate was measured in mol/(L x s)and all concentrations in mol/L

a)L/(mol x s)
b)L2/(mol2 x s)
c)L3/(mol3 x s)
d)mol2/(L2 x s)

I think it's b) but d) is very tempting

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  1. rate = k(A)2 is the rate equation for a second order reaction.

    rate = mol/L*s
    concn = moles/L

    mol/L*s = k(mol/L)^2

    solve for k. Multiply both sides by L^2/mol^2 which should give you
    (mol/L*s)x(L^2/mol^2) = ??. I don't think it is b or d.

    Here is a site that gives the answer but not exactly how to do it.
    http://en.wikipedia.org/wiki/Rate_equation#Summary_for_reaction_orders_0.2C_1.2C_2_and_n

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  2. Don't you mean divide?

    Don't you get
    L^2mol /mol^2 Lxs

    The thing is idk if it can be reduced to
    L/molxs or A)

    Can it?

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