What would the units of the rate constant k be in a second order equation if rate was measured in mol/(L x s)and all concentrations in mol/L
a)L/(mol x s)
b)L2/(mol2 x s)
c)L3/(mol3 x s)
d)mol2/(L2 x s)
I think it's b) but d) is very tempting
rate = k(A)2 is the rate equation for a second order reaction.
rate = mol/L*s
concn = moles/L
mol/L*s = k(mol/L)^2
solve for k. Multiply both sides by L^2/mol^2 which should give you
(mol/L*s)x(L^2/mol^2) = ??. I don't think it is b or d.
Here is a site that gives the answer but not exactly how to do it.
http://en.wikipedia.org/wiki/Rate_equation#Summary_for_reaction_orders_0.2C_1.2C_2_and_n
Don't you mean divide?
Don't you get
L^2mol /mol^2 Lxs
The thing is idk if it can be reduced to
L/molxs or A)
Can it?
You are correct! The units of the rate constant (k) in a second-order reaction can be determined by examining the rate equation. In a second-order reaction, the rate equation can be written as:
rate = k[A]^2
where [A] is the concentration of the reactant A.
To determine the units of k, you can consider the units of rate and concentration. In the given scenario, rate is measured in mol/(L x s) and concentration is measured in mol/L.
Substituting the units into the rate equation, we have:
mol/(L x s) = k * (mol/L)^2
Simplifying this equation, we find:
mol/(L x s) = k * (mol^2/L^2)
Comparing the units on both sides of the equation, we determine that the units of k are L^2/(mol^2 x s).
So, the correct answer is b) L^2/(mol^2 x s).
To determine the units of the rate constant, we can use the rate equation for a second-order reaction:
rate = k[A]^2
where [A] represents the concentration of the reactant.
In this case, the rate is measured in mol/(L x s) and the concentration is measured in mol/L.
Let's plug in the units and solve for the units of k:
mol/(L x s) = k * (mol/L)^2
By canceling out the units on both sides of the equation, we can determine the units of k:
L^-1 x s^-1 = k * L^2 / mol^2
Rearranging the expression, we get:
L^-1 x s^-1 = k * L^2 * mol^-2
Combining all the units, we find that the units of k are L^2 / (mol^2 x s).
Therefore, the correct answer is b) L^2/(mol^2 x s).