What is the overall order of reaction for the elementary system A+2B=products?
a)0
b)1
c)2
d)3
e)5
Can somebody explain this question to me. I don't get it.
This isn't quite the same as the order of a rate equation. Here is a site that may help you get started.
http://www.science.uwaterloo.ca/~cchieh/cact/c123/elmntary.html
Certainly! This question is asking about the overall order of the reaction for the elementary system A + 2B = products. The overall order of a reaction refers to the sum of the exponents in the rate law equation that represents the relationship between the concentrations of reactants and the rate of the reaction.
To determine the overall order of the reaction, we need to know the rate law equation for this specific reaction. The rate law equation is generally determined experimentally by measuring the reaction rate at different concentrations of the reactants.
However, in this case, we are given the stoichiometry of the reaction, which can provide some insights. The stoichiometry tells us that the reaction involves one molecule of A and two molecules of B. Based on this information, we can make the following observations:
1. The reactant A is involved in only one term in the balanced equation, indicating that its concentration affects the rate of the reaction directly.
2. The reactant B is involved in a term consisting of two molecules, suggesting that its concentration has a squared (power of 2) dependence on the rate of the reaction.
From these observations, we can conclude that the rate law equation for this reaction will have the form:
Rate = k[A]^m[B]^n
Where k is the rate constant, [A] is the concentration of A, [B] is the concentration of B, and m, n are the exponents that determine the order of the reaction with respect to A and B, respectively.
Using the above observations, we can deduce that the rate law equation will be:
Rate = k[A]^1[B]^2
Combining the exponents, we find that the overall order of the reaction is (1 + 2) = 3.
Therefore, the correct answer is (d) 3.