The instant a traffic light turns green a car that has been waiting at the light starts forward with a constant acceleration of 10 ft/s^2. At the same instant a truck traveling at a constant 30 ft/s overtakes and passes the car.

1. how far beyond the starting point will the car overtake the truck.
2. how fast willl the car be traveling

The distance both travel is the same

dcar= 1/2 a t^2
dtruck=10 t
set those equal, and solve for t.

then, knowing t, you can find the velocity of the car (a t) and how far it went (1/2 a t^2)

pls ans. dis tnx

i need help:((

To find the solution to these questions, we can use the equations of motion under constant acceleration. There are three important equations we will be using:

1. Velocity after time t, v = u + at
2. Displacement after time t, s = ut + (1/2)at^2
3. Velocity squared, v^2 = u^2 + 2as

Let's solve each question step-by-step.

1. To determine how far beyond the starting point the car overtakes the truck, we need to find the time at which this occurs and then calculate the displacement.

Given:
Acceleration of the car, a = 10 ft/s^2
Initial velocity of the car, u = 0 ft/s (since it starts from rest)
Velocity of the truck, v_truck = 30 ft/s

First, let's find the time taken for the car to catch up to the truck. We can use the equation v = u + at, where v is the final velocity and t is the time taken.

For the truck:
v_truck = u + a_truck * t

Since the truck has a constant velocity (no acceleration), a_truck = 0, and v_truck = u_truck = 30 ft/s.

30 ft/s = 0 ft/s + 0 * t
30 ft/s = 0 ft/s

As we can see, the truck's velocity does not depend on time. Therefore, the car will never overtake the truck, and there is no displacement beyond the starting point.

2. To find the final velocity of the car, we can use the equation v = u + at:

Given:
Acceleration of the car, a = 10 ft/s^2
Initial velocity of the car, u = 0 ft/s (since it starts from rest)
Time taken, t

We want to find the velocity of the car when it overtakes the truck, so we need to find the time at which this occurs.

Using the equation v = u + at:

Final velocity of the car, v_car = 0 ft/s + 10 ft/s^2 * t

Since we don't know the exact time at which the car overtakes the truck, we cannot calculate the final velocity without more information.