At a carnival, there is a game where you throw a coin on a colored square. You are given 3 coins and can land on any square more than once. What is the probability of landing on a red square on your first toss, a red square on your second toss, and a white square on your third toss?
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How many squares of each color are there? Are they all the same size?
To find the probability of landing on a red square on the first toss, a red square on the second toss, and a white square on the third toss, we need to first determine the total number of possible outcomes and then count the number of favorable outcomes.
Step 1: Determine the total number of possible outcomes.
Since there are 3 coins and each coin can land on any of the colored squares (red or white), there are 2 possible outcomes for each coin toss. Therefore, the total number of possible outcomes is 2^3 = 8.
Step 2: Count the number of favorable outcomes.
In this case, a favorable outcome is when we land on a red square on the first toss, a red square on the second toss, and a white square on the third toss. The possible sequences of outcomes that fulfill this condition are:
RRW, RWR, and WRR.
Therefore, there are 3 favorable outcomes.
Step 3: Calculate the probability.
The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.
In this case, the probability of landing on a red square on the first toss, a red square on the second toss, and a white square on the third toss is P = Number of favorable outcomes / Total number of possible outcomes.
Thus, P = 3/8.
Therefore, the probability of landing on a red square on the first toss, a red square on the second toss, and a white square on the third toss is 3/8 or 0.375.