A certain spring stretches 6 cm when a load of 30 N is suspended from it. How much will the spring stretch if 41 N is suspended from it?
solve for the spring constant: k=Force/distance.
then, solve for the new displacement
41=k * x solve for x
dunno
~~4.3
To determine the spring's stretch for a load of 41 N, we need to establish the relationship between force and stretch for the spring. This relationship is described by Hooke's Law, which states that the force exerted by a spring is directly proportional to its displacement or stretch.
Hooke's Law can be expressed as:
F = kx
Where:
F is the force applied to the spring,
k is the spring constant, and
x is the displacement or stretch.
To find the spring constant (k) for this particular spring, we can use the information given. We know that when a load of 30 N is suspended, the spring stretches 6 cm.
Rearranging Hooke's Law, we have:
k = F / x
k = 30 N / 6 cm
k = 5 N/cm
Now that we know the spring constant, we can use it to find the stretch (x) for a load of 41 N.
Again using Hooke's Law:
F = kx
Rearranging for x:
x = F / k
x = 41 N / 5 N/cm
x = 8.2 cm
Therefore, if a load of 41 N is suspended from this spring, it will stretch approximately 8.2 cm.