Algebra HELP!!

Write the equation of the line that contains the points (2, 2) and (-3, 12).

Here is part of the answer. Can you identify the missing part?

y = -2x + ___

I think it's 12


You've got the slope so use
y-y1=m(x-x1) where (x1,y1) is either point.
If you use (2,2), then y-2=-2(x-2)
I don't think it's 12, but verify this yourself.


I don't understand!Can you explain it better please?


I don't get it either!!


This is not a very good format for teaching, it's designed for helping. You both need to learn the basic formulas and concepts.
Slope is the change in y over x as you move along a line. The y intercept is where the line crosses the y-axis.
In the formula y=mx+b m is slope and b is the intercept.
If you're given a point and the slope you use the point slope form of the line which is
y-y1 = m(x-x1) where (x1,y1) is the given point and m is the slope; x and y are simply variables.

Another way to answer the question
Write the equation of the line that contains the points (2, 2) and (-3, 12).

Here is part of the answer. Can you identify the missing part?
y = -2x + ??
would be to substitute either point and solve for the ?? as
2= -2*2 + ?? or 6=?? so the intercept is 6.


oh so the answer is......y=2x+6???
I think that's it?Or am I suppposed to multiply!!


Yes, that's the correct answer. Test it to be sure.


sure


what is the answer for this (-1,-1), slope = 2

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  1. this was posted 8 months after I was born its still not answered wow we need Hal here

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