PHYSIC

a solid aluminum ingot weighs 89N in air a)what is the volume b)the ingot is suspended from a rope and totally immersed in water. what is the tension in the rope(the apparent weight of the ingot in water)?

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asked by KELLY
  1. mass = W/g = 9.08 kg

    (a) For the volume, divide the above mass by the density of aluminum, which you should look up.

    (b) Apparent weight = Actual weight - buoyancy

    = 89 N - (Volume)*(water density)*(g)

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    posted by drwls

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