Algebra

graph the equation x-3=y (where do I plot the points?)

find the intercepts and then graph:
5x+4y=20

find the intercepts and then graph:
1.4x-1.3y=3.64

graph the equation using slope and y-intercept:
y=10/7x +4

graph using slope and y-intercept:
x+2y=8

graph by plotting points x=2

graph x-3=y

graph 5x + 4y=20

find the intercepts and graphj:
1.4x - 1.3y = 3.64

graph using slope and y-intercept:
y=10/7x + 4

graph using slope and y-intercept:
x + 2y = 8

graph x=2 ... what plots are pointed? thought it was just 2 on the y axis but the system won't take that answer?

graph y = -2

what is the slop of x+9=y

find the slope-intercept of 9 and y intercept (0,4)

find slope intercept of 3.3 and y intercept (0,-2)

find an equation of the line having given the slope and containing the given point m = 8, (2,1)

find an equation of the line having given the slope and containing the given point m=7/8, (5-9)

find an equation of the line given the pair of points:
(1/4, -1/3) and (3/4, 3)
what is the equation of the line?

write an equation of the line containing the given point and parallel to the given line - express answer in y=mx+b:
(7,8); x + 3y = 5

write an equation of the line containing the given point and parallel to the given line - express answer in y=mx+b:
(-7, 4); 3x=5y+4

write an equation of the line containing the given point and parallel to the given line - express answer in y=mx+b:
(3,4); 9x + y =7

write an equation of the line containing the given point and perpendicular to the given line:
(2, -5); 2x + 3y = 8

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  1. Perpendicular slopes are negative reciprocals of each other (the product of one times the other is -1).

    In y=mx+b m is the slope and b is the y intercept.

    To find intercepts, just find (0,?) (?,0)

    Parallel lines have the same slope.

    Horizontal lines have a slope of zero, whereas vertical lines have no slope but that is better called an undefined slope. 0/something versus something/0.

    slope= rise or fall/run

    The point slope is y-y1=m (x-x1)

    For intercept, think of the point at which something touches the respective axis.

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  2. 1. Graph X - 3 = Y or Y = X - 3
    Let Y = 0 and solve for X: X = 3,
    Let x = 0 and solve for Y: Y = -3
    The points are: (0,-3), (3,0).

    2. 5X + 4Y = 20
    X-intercept: Let Y = 0, solve for X,
    X = 4.
    Y-intercept: Let X = 0, solve for Y.
    y = 5.

    3. 1.4X - 1.3Y = 3.64
    X-int: Let y = 0, X = 2.6, (2.6,0).
    Y-int: Let X = 0, Y = 2.8, (0,-2.8).

    4. Y = 10/7X + 4 Let X = 0, Y = 4,
    (0,4), Let y = 0, X = 2.1 , (2,1 , 0)

    6. X = 2. This is a vertical line 2
    units to the right of Y axis. X = 2
    for all values of Y: (2,0),(2,2),(2,4).

    7. Y = -2.This is a horizontal line 2
    units below the X-axis. Y = -2 for all
    values of X: (0,-2),(2,-2),(4,-2).

    8. X + 9 = Y or Y = X + 9, Y = mX + b,
    m = coefficient of X = 1.

    9. m = 9, (0,4). Y = mX + b,
    Equation: Y = 9X + 4.

    11. m = 8, (2,1), Y = mX + b,
    1 = 8*2 + b, b = -15, Y = 8X -15.

    13. (1/4,-1/3),(3/4,3).
    m = (3 + 1/3)/(3/4 -1/4) =(10/3)/(2/4)
    = 6 2/3 = 20/3, Y = (20/3)X -2.

    14. (-7,4), 3X = 5Y + 4. 3X -5Y = 4,
    m = -A/B =-3/-5 = 3/5 = m2, Y = mX + b
    4 = 3/5*-7 + b, b = 41/5 = 8 1/5.
    Y = 3/5X + 41/5.

    16. (2,-5), 2X + 3Y = 8, m = -A/B = -2/3, m2 = 3/2 = negative reciprocal of
    m1. Y = mX + b, -5 = 3/2*2 + b, b=-8
    Y = 3/2X -8.

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  3. 5r333333333333333333333333333

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