What is the potential difference across the 10 and 20 ohm resistor in the figure
there is a battery of 15V with two in series resistors of 10 Ohm and 20 ohm
because v=IR, and both have the same current, then voltage has to be in proportion to resistance.
V20= 20/30 * 15
v10= 10/30 * 15
To find the potential difference across a resistor, you can use Ohm's Law which states that the potential difference (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R). In this case, we have a battery with a voltage of 15V and two resistors in series with resistances of 10 ohms and 20 ohms.
To find the current flowing through the circuit, we can use Kirchhoff's circuit laws. In a series circuit, the current flowing through each component is the same. So, the current flowing through the resistors will be the same as the current flowing from the battery.
To calculate the current (I), we can use Ohm's Law: I = V/R, where V is the battery voltage and R is the equivalent resistance of the circuit.
In a series circuit, the total resistance is equal to the sum of the individual resistances. So, the equivalent resistance (R_eq) for the two resistors in series can be calculated as:
R_eq = R1 + R2
In this case, R1 = 10 ohms and R2 = 20 ohms, so:
R_eq = 10 + 20 = 30 ohms
Now that we know the equivalent resistance, we can calculate the current flowing through the circuit:
I = V / R_eq = 15 V / 30 ohms = 0.5 A
Since the current is the same for each resistor in a series circuit, the potential difference across each resistor is given by:
V1 = I * R1 = 0.5 A * 10 ohms = 5 V
V2 = I * R2 = 0.5 A * 20 ohms = 10 V
Therefore, the potential difference across the 10 ohm resistor is 5 V, and the potential difference across the 20 ohm resistor is 10 V.