how many grams of AgNO3 would need to be dissolved in 1 liter, 500mL, and 100mL in order to make a 1M solution? need to show work and answers are in grams....????
You have three problems here. The first one, g AgNO3 in 1 L.
M = moles/L
You now M and L, solve for moles. Then
moles = grams/molar mass. You know moles and molar mass, solve for grams. By the way, note that the 1 L is 1 L of solution (AFTER the AgNO3 is dissolved the final volume is made to exactly 1 L---as distinguished from adding the AgNO3 to 1 L of water). The othres are the same way; the only difference is the volume changes.
To calculate the amount of AgNO3 (silver nitrate) needed to make a 1M (1 mole per liter) solution, you need to consider the molar mass of AgNO3 and the volume of the solution.
1. Firstly, find the molar mass of AgNO3:
- AgNO3 = (1 x atomic mass of Ag) + (1 x atomic mass of N) + (3 x atomic mass of O)
- AgNO3 = (1 x 107.87 g/mol) + (1 x 14.01 g/mol) + (3 x 16.00 g/mol)
- AgNO3 = 107.87 g/mol + 14.01 g/mol + 48.00 g/mol
- AgNO3 = 169.88 g/mol
2. Now, calculate the amount of AgNO3 needed for each volume:
a. 1 liter (1000 mL) of 1M AgNO3 solution:
- Molar mass of AgNO3 = 169.88 g/mol
- Moles of AgNO3 needed = 1 mole/L (1M) x 1 L = 1 mole
- Grams of AgNO3 needed = Moles of AgNO3 needed x Molar mass of AgNO3
- Grams of AgNO3 needed = 1 mole x 169.88 g/mol = 169.88 grams
b. 500 mL of 1M AgNO3 solution:
- First, convert the volume to liters: 500 mL ÷ 1000 mL/L = 0.5 L
- Moles of AgNO3 needed = 1 mole/L (1M) x 0.5 L = 0.5 moles
- Grams of AgNO3 needed = Moles of AgNO3 needed x Molar mass of AgNO3
- Grams of AgNO3 needed = 0.5 moles x 169.88 g/mol = 84.94 grams
c. 100 mL of 1M AgNO3 solution:
- First, convert the volume to liters: 100 mL ÷ 1000 mL/L = 0.1 L
- Moles of AgNO3 needed = 1 mole/L (1M) x 0.1 L = 0.1 moles
- Grams of AgNO3 needed = Moles of AgNO3 needed x Molar mass of AgNO3
- Grams of AgNO3 needed = 0.1 moles x 169.88 g/mol = 16.988 grams
Therefore, to make a 1M AgNO3 solution, you would need to dissolve 169.88 grams of AgNO3 in 1 liter, 84.94 grams in 500 mL, and 16.988 grams in 100 mL.