what is the distance between the points (-1,7) and (5,7)?
why isnt anyone answering my question
The distance is the hypotenuse of a right triangle where one leg is the x distance and the other leg is the y distance. In this case, the y values are the same so the distance between the points is simply the x distance.
distance between any two points (a,b) and (c,d)
= √[(a-c)^2 + (b-d)^2]
so for yours
distance = √(6^2 + 0^2)
= √36 = 6
since for your points have the same y value, thus have the same height, they lie in a horizontal line.
Therefore we could have just taken the horizontal distance from -1 to 5, which of course is 6
To find the distance between two points in a coordinate plane, you can use the distance formula. The distance formula is derived from the Pythagorean theorem and can be written as:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Where (x1, y1) and (x2, y2) are the coordinates of the two points and d represents the distance between them.
In this case, the coordinates of the two points are (-1,7) and (5,7). So, we can substitute these values into the distance formula:
d = √((5 - (-1))^2 + (7 - 7)^2)
Simplifying:
d = √((5 + 1)^2 + 0^2)
d = √(6^2 + 0^2)
d = √(36 + 0)
d = √36
d = 6
Therefore, the distance between the points (-1,7) and (5,7) is 6 units.