3m^3 + 27m = 3m(m^2 + 9)

= 3m(m + 3)(m – 3)
I miss something? is this complete?

Your final answer is incorrect

stop at
3m(m^2 + 9)

we cannot factor the SUM of squares, only the difference of squares.
Had it been 3m^3 - 27m , your final would have been correct.

Submit your question at tutoteddy

and get the answer. They charge only 99 cents for every three math problem.

Yes, your simplification is correct. You have successfully factored the expression 3m^3 + 27m as 3m(m + 3)(m – 3). This is the complete factorization of the given expression. To arrive at this result, you used the distributive property and factored out the greatest common factor, which is 3m. Then, you applied the difference of squares formula to factor the remaining quadratic expression, m^2 + 9, as (m + 3)(m – 3). Thus, your factorization is complete.