what mass of silver nitrate (AgNO3) is required to prepare 400 grams of a 3.50% solution of AgNO3?
Options:
1. 0.00875 g
2. 114.28 g
3. 1400 g
4. 14 g
14g
I put it in and it's right.
(g/400 g soln) = 0.035
solve for g.
To calculate the mass of silver nitrate (AgNO3) required to prepare a 3.50% solution, you can use the equation:
Mass of AgNO3 = (Percentage concentration / 100) * Mass of solution
Given:
Percentage concentration = 3.50%
Mass of solution = 400 grams
Substituting the values into the equation:
Mass of AgNO3 = (3.50 / 100) * 400
Mass of AgNO3 = 0.035 * 400
Mass of AgNO3 = 14 grams
Therefore, the mass of silver nitrate (AgNO3) required to prepare 400 grams of a 3.50% solution of AgNO3 is 14 grams.
The correct option is 4. 14 g
To calculate the mass of silver nitrate (AgNO3) required to prepare a 3.50% solution, you need to know two things:
1. The total mass of the solution: 400 grams
2. The concentration of AgNO3 in the solution: 3.50%
The concentration of a solution is defined as the ratio of the mass of solute (AgNO3) to the mass of the entire solution, multiplied by 100%.
So, to calculate the mass of AgNO3 in the solution, you can use the formula:
Mass of AgNO3 = (Concentration of AgNO3 / 100%) x Mass of solution
Plugging in the values you have:
Mass of AgNO3 = (3.50 / 100) x 400
Mass of AgNO3 = 0.035 x 400
Mass of AgNO3 = 14 grams
Therefore, the correct answer is option 4. 14 g.