For fluoracetic acid the highest Boltzmann distribution is when the dihedral angle is at 0 degrees. However, going from chloro- to bromoacetic acid, an increasing dip in the Boltzmann distribution occurs at 0 degrees. What is responsible for this "dip?" (HINT: look at how the structure of the molecule changes as the halogen atom rotates around toward the hydrogen atom attached to the oxygen atom.)

Question

For fluoracetic acid the highest Boltzmann distribution is when the dihedral angle is at 0 degrees. However, going from chloro- to bromoacetic acid, an increasing dip in the Boltzmann distribution occurs at 0 degrees. What is responsible for this "dip?" (HINT: look at how the structure of the molecule changes as the halogen atom rotates around toward the hydrogen atom attached to the oxygen atom.)

A. Increasing halogen atom size.
B. Decreasing acid strength.
C. Shortening of the C-C bond.
D. Increasing electronegativity.
E. Higher dipole values going from F to Cl to Br.

Answer 1

its not decreasing acid strength

and its not increasing electronegativity
GLuckkk!

Answer 2

my bad answers changed. it's increasing halogen atom size.

Answer 3

Yep, increasing halogen atom size. Thanks. =)

Answer 4

increasing halogen atom size is correct

Answer 5

increasing halogen size :)

Answer 6

its not decreasing acid strength

it's C

my bad answers changed. it's increasing halogen atom size.

Yep, increasing halogen atom size. Thanks. =)

increasing halogen atom size is correct

increasing halogen size :)

increasing halogen size is right! :)