"A 5000kg helicopter accelerates upwards at 0.50m/s^2 while lifting a 2000kg car. What is the lift force exerted by the air on the propellers?"
I don't understand what the problem is asking for.
force= total mass(g+a)
I figured it out, thank you!
The problem is asking for the lift force exerted by the air on the propellers of the helicopter. The lift force is the force that opposes the weight of the helicopter and allows it to lift off the ground.
The problem is asking for the lift force exerted by the air on the propellers of the helicopter. To find this, we can use Newton's second law, which states that force is equal to mass multiplied by acceleration (F = m * a).
First, let's break down the weights involved. The weight of the helicopter (W_h) is equal to its mass (m_h) multiplied by the acceleration due to gravity (g = 9.8m/s^2). So, W_h = m_h * g.
Similarly, the weight of the car (W_c) is equal to its mass (m_c) multiplied by the acceleration due to gravity (g). So, W_c = m_c * g.
Now, we need to consider the acceleration of the helicopter when it lifts the car. The net force acting on the system (helicopter and car) is equal to their combined weight (W_h + W_c) subtracted from the lift force (F_lift) exerted by the air on the propellers. We can express this as:
net force = F_lift - (W_h + W_c)
Since the net force is equal to the total mass (m_total) of the system multiplied by the acceleration (a) of the system, we have:
m_total * a = F_lift - (W_h + W_c)
The total mass of the system (m_total) is the sum of the masses of the helicopter (m_h) and the car (m_c).
Now we can substitute the known values into the equation and solve for the lift force (F_lift).