"Two girls, one of mass 40kg and the other of mass 60kg, are standing side by side in the middle of a frozen pond. One pushes the other with a force of 360N for 0.10s. The ice is essentially frictionless. What is each girl's acceleration?"

Question

"Two girls, one of mass 40kg and the other of mass 60kg, are standing side by side in the middle of a frozen pond. One pushes the other with a force of 360N for 0.10s. The ice is essentially frictionless. What is each girl's acceleration?"

Answer 1

To find each girl's acceleration, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.

First, let's find the net force acting on each girl. The girl with a mass of 40 kg is pushed with a force of 360 N, and the girl with a mass of 60 kg is the one pushing. Since the girls are standing side by side, the force exerted by the girl with a mass of 60 kg on the girl with a mass of 40 kg will be the same. Therefore, the net force acting on each girl is 360 N.

Now, let's find each girl's acceleration using the formula:

acceleration = net force / mass

For the girl with a mass of 40 kg:

acceleration = 360 N / 40 kg
acceleration = 9 m/s^2

For the girl with a mass of 60 kg:

acceleration = 360 N / 60 kg
acceleration = 6 m/s^2

Therefore, the girl with a mass of 40 kg has an acceleration of 9 m/s^2, while the girl with a mass of 60 kg has an acceleration of 6 m/s^2.

Answer 2

To find the acceleration of each girl, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

First, let's calculate the net force acting on each girl. The force exerted by the first girl on the second girl is 360N.

For the first girl:
Mass (m1) = 40 kg

For the second girl:
Mass (m2) = 60 kg

Now, we can calculate the acceleration of each girl using the formula:

Acceleration (a) = Net Force (F) / Mass (m)

For the first girl:
Acceleration of the first girl (a1) = 360N / 40kg

For the second girl:
Acceleration of the second girl (a2) = 360N / 60kg

Let's calculate the values:

Acceleration of the first girl (a1) = 360N / 40kg = 9 m/s^2

Acceleration of the second girl (a2) = 360N / 60kg = 6 m/s^2

Therefore, the acceleration of the first girl is 9 m/s^2, and the acceleration of the second girl is 6 m/s^2.

Answer 3

the force on each is 360 N

a = 360/m
for each m