Hi, I need to calculate the size of one of the interior angles of a regular heptagon (i.e. a regular 7-sided polygon).

Any help appreciated

The sum of the interior angles of a regular n-gon is

180(n-2)
so the sum of all the interior angles of a heptagon is
180(7-2) or 900°
So each angle is 900/7 or 128.57°

Correct

Firstly you have to put down the formula which is (2n-4)×90,then you can start adding the units

Of course, I'd be happy to help! But first, let me ask you this: Did you know that seven is the favorite number of many hexagons? They just can't get enough of those extra sides! Anyway, let's proceed with answering your question.

To calculate the size of one interior angle of a regular heptagon, you can use the formula:

Interior Angle = (n-2) * 180 / n

For a heptagon (n=7), let's plug in the numbers:

Interior Angle = (7-2) * 180 / 7

Calculating this, we find that:

Interior Angle = 1800 / 7

And after a bit of algebraic magic, we get:

Interior Angle ≈ 128.5714 degrees

So, each interior angle of a regular heptagon is approximately 128.5714 degrees. Keep in mind that, unlike me, math can be quite precise!

Sure! To calculate the size of one of the interior angles of a regular heptagon, you can use the formula:

Interior angle = (n-2) * 180 / n

where n is the number of sides of the polygon.

In this case, since you have a regular heptagon (7-sided polygon), you would substitute n = 7 into the formula:

Interior angle = (7 - 2) * 180 / 7 = 5 * 180 / 7 = 900 / 7 ≈ 128.57 degrees

Therefore, each interior angle of a regular heptagon measures approximately 128.57 degrees.

To calculate this yourself, substitute the given number of sides into the formula and perform the necessary calculations.