A man’s will left $75,000 to his wife, son and daughter in such a way that his son’s share was 3 times the daughter’s share, while the wife received as much as the son and daughter together. How much did each receive?

a man distributed his proprty worth of 80000among his wife, 4 sonsabd 2 daughters, wife get 1/4, sons get double of what daughter get

To solve this problem, we can use a system of equations.

Let's assume the daughter's share is represented by 'x'. According to the problem, the son's share is 3 times the daughter's share, so his share would be 3x.

The wife received as much as the son and daughter together, so the total amount the wife received is (3x + x), which simplifies to 4x.

The problem states that the total amount left in the will is $75,000. Therefore, we can write the equation:

x + 3x + 4x = 75,000

Now, we need to solve this equation to find the values of x, 3x, and 4x.

Combining like terms, we have:
8x = 75,000

To find the value of x, we divide both sides of the equation by 8:
x = 75,000 / 8
x = 9,375

Now that we have the value of x, we can find the values of 3x and 4x.
3x = 3 * 9,375 = 28,125
4x = 4 * 9,375 = 37,500

Therefore, the daughter received $9,375, the son received $28,125, and the wife received $37,500.

daughter's share --- x

son's share ---- 3x
wife's share --- 3x + x or 4x

x + 3x + 4x = 75000

easy to solve for x ....

2+2