if the specific heat of aluminum is 0.21 cal/g degree C, how much heat is givin off when 10 grams of aluminum is cooled from .50 to .10 degress
q = M C (delta T)
10x.21x.0.4 calories
Are you sure you did not mean 50 to 10 degrees?
290
To calculate the amount of heat given off when 10 grams of aluminum is cooled from 0.50 to 0.10 degrees Celsius, we can use the formula:
Q = m * C * ΔT
Where:
Q = heat (in calories)
m = mass (in grams)
C = specific heat (in cal/g°C)
ΔT = change in temperature (in °C)
Plugging in the given values:
m = 10 grams
C = 0.21 cal/g°C
ΔT = 0.10 - 0.50 = -0.40 degrees Celsius (change in temperature is negative since it is a cooling process)
Now we can calculate the heat (Q):
Q = 10 g * 0.21 cal/g°C * (-0.40°C)
Q = -8.4 cal
Therefore, when 10 grams of aluminum is cooled from 0.50 to 0.10 degrees Celsius, approximately 8.4 calories of heat is given off.
To calculate the heat given off when 10 grams of aluminum is cooled from 0.50 to 0.10 degrees Celsius, you can use the formula:
Q = mcΔT
Where:
Q = heat (in calories)
m = mass (in grams)
c = specific heat capacity (in cal/g°C)
ΔT = change in temperature (in °C)
Let's plug in the given values into the formula:
m = 10 grams
c = 0.21 cal/g°C
ΔT = (final temperature - initial temperature)
ΔT = 0.10°C - 0.50°C
ΔT = -0.40°C
Note: Since the temperature is decreasing, the value of ΔT will be negative.
Now we can calculate the heat (Q):
Q = (10 grams) x (0.21 cal/g°C) x (-0.40°C)
Q = -0.84 calories
Therefore, 10 grams of aluminum will give off approximately -0.84 calories of heat when cooled from 0.50 to 0.10 degrees Celsius. The negative sign indicates that heat is being released.