I cannot figure this out. It seems so simple, and I should know it.

The density of tungsten is 19.3g/cm^3
Express this value in lb/ft^3.

I did 19.3g/cm^3 x 2.54cm/inch x 12 inches/1 foot = 588.264.

Now 19.3g x 1 ounce/28g x 16 ounces/lb.
= 11.03.

After reading my answer key, the answer says it is 1.21 x 10^3 lb/ft^3.

I cannot for the life of me figure out what I am doing wrong. Please help.

19.3 g/1 cm^3 * 1 lb/453.59 g

=0.043 lb/cm^3
The grams cancel out.
0.043 lb/cm^3 * 28317.02 cm^3/ft^3=1217.63 lb/ft^3

1217.63 lb/ft^3 = 1.21 lb/ft^3

Thankyou very much

To convert the density of tungsten from grams per cubic centimeter (g/cm^3) to pounds per cubic foot (lb/ft^3), you're on the right track with your conversions. Let's break down the steps and figure out what might be causing the discrepancy.

1. Start with the given density of tungsten: 19.3g/cm^3.

2. Convert cm to inches: Since there are 2.54 cm in an inch, multiply the density by 2.54 to get it in inches:

19.3g/cm^3 * 2.54 cm/inch = 49.022g/inch^3.

3. Convert inches to feet: Since there are 12 inches in a foot, divide the density by 12 to get it in feet:

49.022g/inch^3 / 12 inches/foot ≈ 4.085g/foot^3.

4. Convert grams to pounds: Since there are 453.592 grams in a pound, divide the density by 453.592 to get it in pounds:

4.085g/foot^3 / 453.592g/lb ≈ 0.009lb/foot^3.

So, following these steps, the density of tungsten would be approximately 0.009 lb/ft^3.

It seems there might be errors in your calculations. Double-check the conversions and make sure you're using the correct conversion factors.