How many grams of CH4 are required to produce 43 g of Cu according to the following equation: 4CuO + CH4 --> CO2 + 2H20 + 4Cu?
I already tried to work the problem myself, and I may have gotten this right, but I do not have an answer key to compare to.
#gCH4 = (43gCu) x (1 mol Cu/63.55gCu) x (16.05gCH4/1 mol CH4) x (1 mol CH4/ 4 mol Cu) =
=2.71 mols x 16.05 = 43.57g of CH4.
Is this correct? If not, can someone please show me how to do this correctly. I could have figured it out but I do not have an answer key to work with.
Oh my gosh yes! Thankyou Dr. Bob, you are truelly my saint.
#gCH4 = (43gCu) x (1 mol Cu/63.55gCu) x (16.05gCH4/1 mol CH4) x (1 mol CH4/ 4 mol Cu) =
All of the above is correct AND 2.71 is the correct answer for g CH4. You don't need the next step since you have already multiplied in the above by 16.05 g CH4/1 mol CH4.
=2.71 mols x 16.05 = 43.57g of CH4.
Well, let me first applaud your efforts in trying to work out the problem by yourself. That's commendable! Now, let's see if the answer you came up with is correct.
To find out how much CH4 is required, we can use stoichiometry. From the balanced equation, we can see that 4 moles of Cu are produced for every mole of CH4. Therefore, you were on the right track with your calculations.
Let's do the math together:
Given: 43 g of Cu
Molar mass of Cu = 63.55 g/mol
Using the molar mass of Cu, we can convert grams of Cu to moles of Cu:
43 g Cu × (1 mol Cu / 63.55 g Cu) ≈ 0.676 mol Cu
Now, using the stoichiometric ratio from the balanced equation:
0.676 mol Cu × (1 mol CH4 / 4 mol Cu) ≈ 0.169 mol CH4
To find the grams of CH4, we can multiply the moles by the molar mass of CH4:
0.169 mol CH4 × (16.05 g CH4 / 1 mol CH4) ≈ 2.71 g CH4
So, it looks like your original answer of 2.71 grams of CH4 is correct! Great job, and keep up the good work!
To determine the number of grams of CH4 required to produce 43 g of Cu, you need to follow the stoichiometry of the equation. Here's the correct calculation:
1. Calculate the number of moles of Cu using the given mass:
moles of Cu = 43 g Cu / 63.55 g/mol (molar mass of Cu)
moles of Cu = 0.676 mol Cu
2. Use the stoichiometric ratio between Cu and CH4 to find the moles of CH4:
moles of CH4 = moles of Cu × (1 mol CH4 / 4 mol Cu)
moles of CH4 = 0.676 mol Cu × (1 mol CH4 / 4 mol Cu)
moles of CH4 = 0.169 mol CH4
3. Finally, convert the moles of CH4 to grams:
mass of CH4 = moles of CH4 × molar mass of CH4
mass of CH4 = 0.169 mol CH4 × 16.04 g/mol (molar mass of CH4)
mass of CH4 = 2.71 g CH4
So, the correct answer is 2.71 grams of CH4. Your initial calculation was correct.
Your calculation is almost correct, but there is an error in the last step. Let me walk you through the correct calculation:
First, write down the balanced equation and determine the molar ratios:
4CuO + CH4 --> CO2 + 2H2O + 4Cu
From the equation, you can see that 1 mole of CH4 reacts with 4 moles of Cu.
Now, let's calculate the number of moles of Cu:
43 g of Cu * (1 mol Cu/63.55 g Cu) = 0.677 mol Cu
Next, we can use the molar ratios from the balanced equation to find the moles of CH4:
0.677 mol Cu * (1 mol CH4/4 mol Cu) = 0.169 mol CH4
Finally, convert moles of CH4 to grams:
0.169 mol CH4 * (16.05 g CH4/1 mol CH4) = 2.71 g CH4
So the correct answer is 2.71 g of CH4.
Hope this helps!