Physic

What is the period of revolution of a satellite with mass m that orbits the earth in a circular path of radius 7820 km (about 1450 km above the surface of the earth)?

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  1. F = m a
    Force of gravity = m v^2/r

    G m Me /r^2 = m v^2/r
    where G is Newton's gravitational constant and Me is mass of earth
    r = 7,820,000 meters

    G Me = v^2 r

    v^2 = G Me/r
    solve for v

    (2 pi r)/v = period

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