A space station, in the form of a wheel 110 m in diameter, rotates to provide an "artificial gravity" of 3.00 m/s2 for persons who walk around on the inner wall of the outer rim. Find the rate of rotation of the wheel (in revolutions per minute) that will produce this effect.

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  1. 3 = v^2/r

    3 * 55 = v^2

    v = 12.8 m/s

    Time for revolution = 2 pi r/v
    = 2 pi * 55/12.8 = 26.9 seconds = .448 minutes

    1/.448 = 2.23 revs/minute

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  2. It is very good site short and best answers

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