If 1.000 kcal of heat is added to 1.700 L of oxygen in a cylinder at constant pressure of 1.00 atm, the volume increases to 2.100 L. Calculate the total energy change for this process.

To calculate the total energy change for this process, we need to find the change in internal energy, ΔU, using the first law of thermodynamics:

ΔU = q - w,

where ΔU is the change in internal energy, q is the heat added, and w is the work done.

First, let's find the work done, w. Since the pressure is constant, we can find it using the formula:

w = -PΔV,

where P is the pressure and ΔV is the change in volume.

Given:
Heat added, q = 1.000 kcal
Initial volume, V1 = 1.700 L
Final volume, V2 = 2.100 L
Pressure, P = 1.00 atm

Now, let's calculate the change in volume:

ΔV = V2 - V1 = 2.100 L - 1.700 L = 0.400 L.

Next, plug the values into the formula for work done:

w = -(1.00 atm)(0.400 L) = -0.400 L·atm.

Now, we can calculate the change in internal energy:

ΔU = q - w = 1.000 kcal - (-0.400 L·atm) = 1.000 kcal + 0.400 L·atm.

Therefore, the total energy change for this process is 1.000 kcal + 0.400 L·atm.

To calculate the total energy change for this process, we can use the concept of work done by a gas.

First, let's calculate the work done during the process:

Work done (W) = P * ΔV

Where:
P is the pressure (1.00 atm)
ΔV is the change in volume (2.100 L - 1.700 L = 0.400 L)

W = 1.00 atm * 0.400 L
W = 0.400 atm * L (Note: 1 atm * 1 L = 1 J)

Now, let's convert the energy added (1.000 kcal) into joules:

1 kcal = 4184 J (conversion factor)
1.000 kcal = 1.000 * 4184 J
1.000 kcal = 4184 J

Next, let's calculate the total energy change:

Total energy change = Energy added - Work done

Total energy change = 4184 J - 0.400 atm * L

Note that 0.400 atm * L is equal to 0.400 * 1 J (because 1 atm * 1 L = 1 J)

Total energy change = 4184 J - 0.400 J
Total energy change = 4183.6 J

Therefore, the total energy change for this process is approximately 4183.6 joules.

1000 kcal = 4184 kJoules is added to the mixture, but some work is done by the expanding gas. The work is equal to P x (change in volume). Make sure P is in Newtons/m^2. Then P x 9change in volume0 will be in Joules. Remember to convert 1 atm to Newtons/m^2 (Pascals)

The difference between heat added and work done is the internal energy change of the oxygen.

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