The sum of 14 and twice a number y is equal to 78 ?
14 + 2y = 78
78 - 14 = 64
2y = 64
64 / 2 = 32
y = 32
14+2y=78
-14 -14
__________
2y=64
_ _
2 2
y=32
Dfrom point a to point b=215miles
VELOCITYaverage=change in distance/change in time
=215miles/4.5hrs
Approx.=47.8 or 48mph
To solve this problem, we need to set up an equation based on the given information.
Let's break down the information given:
The sum of 14 and twice a number y: 14 + 2y
(This means we are adding 14 to twice the number y.)
is equal to 78: 14 + 2y = 78
Now, we need to solve this equation to find the value of y.
To isolate y, we will need to get rid of the 14 on the left side of the equation. We can do this by subtracting 14 from both sides:
14 - 14 + 2y = 78 - 14
This simplifies to:
2y = 64
Next, to solve for y, we will divide both sides of the equation by 2:
2y/2 = 64/2
This simplifies to:
y = 32
Therefore, the value of y is 32.