In 1991, the life expectancy of males in ceetain country's was 73.3 years. n 1996, it was 75.8 years. Let E represent the life expectancy in year t and let t reprsent the number of years since 1991.

The linear fuction E(t) that fits the data is E(t)= ______ t + ______.
Round t the nearest tenth.
Use the fnction to predict the life expectancy of males in E(14).
Round to the nearest tenth.

A very similar question was asked two days ago. Work this one the same way. In this case, life expectancy increases 0.5 years per year.

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To find the linear function that fits the given data, we need to determine the rate of change in life expectancy over time.

The rate of change can be calculated by dividing the difference in life expectancy by the difference in years:

Rate of change = (75.8 - 73.3) / (1996 - 1991)

Simplifying this expression, we have:

Rate of change = 2.5 / 5

Rate of change = 0.5

Now, we have the rate of change, we need to find the initial value of life expectancy at t = 0 (1991). We can do this by substituting one of the given data points into the linear function equation.

Using the data point (1991, 73.3), we can substitute t = 0 and E(t) = 73.3 into the equation E(t) = mt + b:

73.3 = 0.5(0) + b

73.3 = b

Therefore, the linear function E(t) is:

E(t) = 0.5t + 73.3

To predict the life expectancy in E(14), we substitute t = 14 into the equation:

E(14) = 0.5(14) + 73.3

E(14) = 7 + 73.3

E(14) = 80.3

Therefore, the predicted life expectancy of males in year 14 is approximately 80.3 years.