find the x and y intercepts of the line given by the equation
8x + 3y = 13
Would it be 13/8 and 13/3?
x intercept when y = 0
13/8 yes
y intercept when x = 0
13/3 yes
yeah, true.
For x intercept, sub y=0 into the equation, and you'll get 13/8
For y intercept, sub x=0 into the equation and you'lll get 13/3
Write an equation in slope-intercept form for the line that satisfies each set of conditions. Passes through (5, -2), parallel to the graph of x+2y=8
To find the x-intercept, where the line intersects the x-axis, we set y=0 in the given equation and solve for x.
So, if we substitute y=0 into the equation 8x + 3y = 13, we get:
8x + 3(0) = 13
8x = 13
x = 13/8
Therefore, the x-intercept is 13/8.
To find the y-intercept, where the line intersects the y-axis, we set x=0 in the given equation and solve for y.
So, if we substitute x=0 into the equation 8x + 3y = 13, we get:
8(0) + 3y = 13
3y = 13
y = 13/3
Therefore, the y-intercept is 13/3.
In conclusion, the x-intercept is 13/8 and the y-intercept is 13/3 for the given equation 8x + 3y = 13.