Again please NO answers! Only on how to solve.
One canned juice drink is 20% orange juice; another is 5% orange juice. How many liters of each should be mixed together in order to get 15L that is 14% orange juice?
.2 x + .05 y = .14 (x+y)
and
x+y = 15
O.J.=(0.14)(15)=2.1 lit ers.
1. 0.2X+0.05Y=2.1
2. X + Y = 15
To solve by elimination,multiply
both sides of equation 1 by(-)5:
-X-o.25Y=-10.5
X + Y = 15
Y = 6 liters @ 5% O.J.
X = 9 liters @ 20 % O.J.
To solve this problem, you need to set up a system of equations based on the given information:
Let's call the number of liters of the 20% orange juice drink "x" and the number of liters of the 5% orange juice drink "y".
Since we want a total of 15 liters of the mixture, we can write the first equation:
x + y = 15
Next, let's consider the orange juice content. We need to find the amount of orange juice in each of the drinks and determine the average:
For the drink that contains 20% orange juice, the amount of orange juice can be calculated as 0.20 * x.
For the drink that contains 5% orange juice, the amount of orange juice can be calculated as 0.05 * y.
The total amount of orange juice in the mixture will be x * 0.20 + y * 0.05.
Since we want the final mixture to have a 14% orange juice content, we can set up the second equation:
(0.20 * x + 0.05 * y) / 15 = 0.14
Now you have a system of two equations:
x + y = 15 (equation 1)
(0.20 * x + 0.05 * y) / 15 = 0.14 (equation 2)
To solve this system of equations, you can use various methods such as substitution, elimination, or graphing. Choose the method that you are most comfortable with to find the values of x and y.