alg

solve: 1 / x + 2 + 1 / x - 2= 1 / x^2 - 4

a)-2
b) 2
c)-1/2
d) 1/2

asked by sean
  1. you probably meant to type
    1/(x + 2) + 1/(x - 2) = 1/(x^2 - 4)

    multiply each term by x^2 - 4, ( which factors to (x+2)(x-2) )

    x-2 + x+2 = 1
    2x = 1
    x = 1/2

    posted by Reiny
  2. multiply both sides by (x+2)(x-2)

    x-2+x+2=1
    x= 1/2

    posted by bobpursley
  3. thanks reiny

    posted by sean

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