An excess of zinc metal is added to 50.0 mL of a 0.100 M AgNO3 solution in a constant-pressure calorimeter. Assuming that the density of the solution is the same as for water, calculate the mass of the solution.
The question doesn't make sense to me. The 50 mL of the AgNO3 solution has a mass of 50.0 g assuming the density of water and the AgNO3 soln is the same; however, that is the mass before an excess of Zn metal is added. I have no idea how much the total material weighs. It all depends upon the amount of Zn added.
50mL of 0.1M = .005 moles of AgNO3, so based on balanced equation, that will react with .0025 moles Zn.
Calculate q(zinc) = -(q(sol) + q(cal))
q(zinc) = -(50*4.18*2.92 + 98.6*2.92)
q(zinc) = -898.19 J
then divide by .0025 moles of Zn reacting (and covert to kJ)
= -306kJ/mol
50mL of 0.1M = .005 moles of AgNO3, so based on balanced equation, that will react with .0025 moles Zn.
Calculate q(zinc) = -(q(sol) + q(cal))
q(zinc) = -(50*4.18*2.92 + 98.6*2.92)
q(zinc) = -898.19 J
then divide by .0025 moles of Zn reacting (and covert to kJ)
= -360kJ/mol
Well, zinc and silver seem to be having a "metal on metal" party in the calorimeter! How delightful! Let's crunch some numbers and get to the bottom of this.
To calculate the mass of the solution, we need to consider the volume and density. Given that the volume of the silver nitrate solution is 50.0 mL, we can assume it has the same density as water, which is approximately 1 g/mL. So, the mass of the solution would be 50.0 grams (since 50.0 mL of water weighs approximately 50.0 grams).
It's important to note that the excess zinc metal won't factor into the mass of the solution, as it is just there to react with the silver nitrate. So, let's just focus on our delightful solution for now.
Voila! The mass of the solution is 50.0 grams. Isn't it funny how math helps us solve even the silliest of problems?
To calculate the mass of the solution, we need to know the density of the solution.
Since the density of the solution is assumed to be the same as water, we can use the density of water at room temperature.
The density of water at room temperature is approximately 1 gram per milliliter (g/mL).
Given that the volume of the solution is 50.0 mL, the mass of the solution can be calculated as follows:
Mass of the solution = Volume of the solution x Density of water
Mass of the solution = 50.0 mL x 1 g/mL
Mass of the solution = 50.0 grams