100 million automobiles contains 1.1 kg of CFC-12
and leaks 25% of its CFC-12(CF2Cl2) into the atmosphere
per year, how much Chlorine in kilograms is added to
the atmosphere each year due to auto air conditioners?
Do you have an equation for the formation of chlorine? Is that Cl total from CFC-12 you want or Cl2 due to the reaction with the atmosphere.Or is there some other interpretation.
find an answer bunch of POS
100 million automobiles contains 1.1 kg of CFC-12
and leaks 25% of its CFC-12(CF2Cl2) into the atmosphere
per year, how much Chlorine in kilograms is added to
the atmosphere each year due to auto air conditioners?
To find out how much chlorine is added to the atmosphere each year due to auto air conditioners, we can follow these steps:
Step 1: Calculate the total amount of CFC-12 (CF2Cl2) leaked into the atmosphere per year.
Given that 100 million automobiles contain 1.1 kg of CFC-12 and leaks 25% of it, we can calculate the amount of CFC-12 leaked per year as follows:
CFC-12_leaked = 100,000,000 automobiles * 1.1 kg * 0.25 = 27,500,000 kg
Step 2: Calculate the amount of chlorine (Cl) in CFC-12.
CFC-12 consists of 1 carbon atom (C), 2 fluorine atoms (F), and 2 chlorine atoms (Cl). Based on its molecular formula, CF2Cl2, we can determine that each molecule of CFC-12 contains 2 chlorine atoms.
Therefore, the number of moles of chlorine in 1 kg of CFC-12 can be calculated as follows:
1 kg CFC-12 * (2 moles Cl / 120.91 g CFC-12) = 0.0165 moles Cl
Step 3: Calculate the total amount of chlorine added to the atmosphere each year.
Finally, we can determine the total amount of chlorine (Cl) added to the atmosphere annually by multiplying the amount of CFC-12 leaked by the amount of chlorine per kilogram of CFC-12:
Chlorine_added = CFC-12_leaked * (0.0165 moles Cl / 1 kg CFC-12) * (35.45 g Cl / 1 mole Cl) = 15,404,250 kg
Therefore, approximately 15,404,250 kilograms of chlorine are added to the atmosphere each year due to auto air conditioners leaking CFC-12.