2.A 4430 kg helicopter accelerates upward at 2.2 m/s2. What lift force is exerted by the air on the propellers?
F= m(g+a)
To find the lift force exerted by the air on the propellers of the helicopter, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
The mass of the helicopter is given as 4430 kg, and the acceleration is given as 2.2 m/s^2. We need to multiply these two values to find the total force exerted by the helicopter.
Force = mass × acceleration
Force = 4430 kg × 2.2 m/s^2
Force = 9746 N
Therefore, the lift force exerted by the air on the propellers of the helicopter is 9746 Newtons.