The heat fusion for napthalene (C10H8) is 18.98 kj/mol and for sodium is 2.60 kj/mol. The amount of heat that would melt 37.0 grams of napthalene would melt how many grams of sodium?

q naphthalene (note spelling)= mass x heat fusion.

Then plug this q into
q Na = mass x heat fusion and solve for mass.

To determine the amount of sodium that would require the same amount of heat as melting 37.0 grams of naphthalene, we need to use the concept of molar ratios and the heat fusion values for both substances.

First, let's convert the mass of naphthalene into moles:

Molar mass of naphthalene (C10H8) = 10 * atomic mass of carbon + 8 * atomic mass of hydrogen
= 10 * 12.01 g/mol + 8 * 1.01 g/mol
= 128.17 g/mol

Moles of naphthalene = Mass of naphthalene / Molar mass of naphthalene
= 37.0 g / 128.17 g/mol
= 0.288 mol

Now we can use the molar ratio between naphthalene and sodium to find the mass of sodium that would require the same amount of heat:

1 mol of naphthalene : 18.98 kJ
1 mol of sodium : 2.60 kJ

Using the ratio of heat fusion:

0.288 mol of naphthalene : x mol of sodium

x = (0.288 mol of naphthalene * 2.60 kJ) / (1 mol of naphthalene)
= 0.7488 kJ

To convert this value to grams, we need to use the molar mass of sodium.

Molar mass of sodium (Na) = 22.99 g/mol

Mass of sodium = Energy required (kJ) / Heat fusion (kJ/mol) * Molar mass (g/mol)
= 0.7488 kJ / 2.60 kJ/mol * 22.99 g/mol
= 6.76 g

Therefore, the heat required to melt 37.0 grams of naphthalene would melt approximately 6.76 grams of sodium.

To find out how many grams of sodium would be melted by the same amount of heat required to melt 37.0 grams of naphthalene, we can use the concept of molar heat of fusion.

First, we need to calculate the number of moles of naphthalene in 37.0 grams. We can do this by using the molar mass of naphthalene, which is 128.17 g/mol.

Moles of naphthalene = Mass of naphthalene / Molar mass of naphthalene
= 37.0 g / 128.17 g/mol
= 0.2882 mol

Since the heat of fusion is given per mole, we can now calculate the amount of heat required to melt 37.0 grams of naphthalene.

Heat required to melt naphthalene = Moles of naphthalene x Heat fusion of naphthalene
= 0.2882 mol x 18.98 kJ/mol
= 5.468 kJ

Now, we can use the heat of fusion of sodium to find out how many grams of sodium would require the same amount of heat.

Heat required to melt sodium = 5.468 kJ

Heat required to melt sodium = Moles of sodium x Heat fusion of sodium
So, Moles of sodium = Heat required to melt sodium / Heat fusion of sodium
= 5.468 kJ / 2.60 kJ/mol
= 2.10 mol

Finally, we can calculate the mass of sodium using the moles of sodium and its molar mass, which is 22.99 g/mol.

Mass of sodium = Moles of sodium x Molar mass of sodium
= 2.10 mol x 22.99 g/mol
= 48.15 g

So, the amount of heat that would melt 37.0 grams of naphthalene would melt approximately 48.15 grams of sodium.