What is the net ionic equation for the reaction Copper (II) chloride and sodium hydroxide?
Write the molecular equation.
CuCl2(aq) + 2NaOH(aq) ==> Cu(OH)2(s) + 2NaCl(aq)
Then the net ionic equation follows:
Cu^+2(aq) + 2Cl^-(aq) + 2Na^+(aq) + 2OH^-(aq) ==> Cu(OH)2(s) + 2Na^+(aq) + 2Cl^-(aq)
Now cancel the ions common to both sides; i.e., cancel 2Cl^- and 2Na^+ to leave
Cu^+2 (aq) + 2OH^-(aq) ==> Cu(OH)2(s)
Check my work closely.
Oh, it's time for a little chemical comedy! The net ionic equation for this reaction would be like watching Cupid dance with an octopus! Here it goes:
2CuCl₂ + 4NaOH → 2Cu(OH)₂ + 4NaCl
Copper (II) chloride and sodium hydroxide waltz together to form copper hydroxide and sodium chloride. It's like a chemical ballroom, but the dance partners swap partners, and everyone ends up happy!
To write the net ionic equation for the reaction between copper (II) chloride and sodium hydroxide, we first need to know the balanced chemical equation:
Copper (II) chloride + Sodium hydroxide → Copper (II) hydroxide + Sodium chloride
The chemical formula for copper (II) chloride is CuCl2, and for sodium hydroxide is NaOH. Copper (II) hydroxide is Cu(OH)2, and sodium chloride is NaCl.
The balanced chemical equation is:
CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl
To write the net ionic equation, we remove the spectator ions, which are ions that don't participate in the actual reaction. In this case, the spectator ions are sodium (Na+) and chloride (Cl-), which appear as reactants and products on both sides of the equation.
The net ionic equation is:
Cu2+ + 2OH- → Cu(OH)2
So, the net ionic equation for the reaction between copper (II) chloride and sodium hydroxide is: Cu2+ + 2OH- → Cu(OH)2
To determine the net ionic equation for the reaction between copper (II) chloride (CuCl2) and sodium hydroxide (NaOH), we need to first write the balanced equation and then identify the spectator ions.
1. Write the balanced equation for the reaction:
CuCl2 + 2NaOH -> Cu(OH)2 + 2NaCl
2. Now, determine the state of each compound involved in the reaction:
- CuCl2: Copper (II) chloride is a soluble salt and dissociates into Cu^2+ and 2Cl^- ions in solution.
- NaOH: Sodium hydroxide is also a soluble compound and breaks down into Na^+ and OH^- ions when dissolved in water.
- Cu(OH)2: Copper (II) hydroxide is an insoluble compound and remains undissociated in aqueous solution.
- NaCl: Sodium chloride is a soluble salt and dissociates into Na^+ and Cl^- ions when dissolved in water.
3. Determine the spectator ions:
The spectator ions are the ions that do not participate in the formation of a precipitate (insoluble product) and are present on both sides of the equation. In this reaction, the spectator ions are Na^+ and Cl^-.
4. Write the net ionic equation:
The net ionic equation includes only the species that are involved in the formation of an insoluble product. Since Cu(OH)2 is insoluble, it is the only product that matters.
Cu^2+ + 2OH^- -> Cu(OH)2
Therefore, the net ionic equation for the reaction between copper (II) chloride and sodium hydroxide is Cu^2+ + 2OH^- -> Cu(OH)2.