My mind is bleeding again. I am trying to figure out the molarity of acetic acid in Vinegar. We used a standard solution of .613 Molars of NaOH. We added 33.75mL of NaOH to completely titrate/neutralize 25mL of Vinegar and we're supposed to be able to figure out the molarity of acidic acid in the vinegar, but I cannot figure this out. Can anybody help me?

Question

My mind is bleeding again. I am trying to figure out the molarity of acetic acid in Vinegar. We used a standard solution of .613 Molars of NaOH. We added 33.75mL of NaOH to completely titrate/neutralize 25mL of Vinegar and we're supposed to be able to figure out the molarity of acidic acid in the vinegar, but I cannot figure this out. Can anybody help me?

Answer 1

moles NaOH = M x L = 0.613 x 0.03375= ??

So moles acidity in the solution (the vinegar) is the same as moos NaOH since the reaction is a 1 mole to 1 mole ratio.

Since moles vinegar is in 25 mL, then
M = moles/L and M vinegar = moles from above/0.025 = ??

OR, if you don't want to go through all the explanations, just use this neat formula (good when 1:1 mole ratio exists as it does in this problem).
mL NaOH x M NaOH = mL vinegar x M vinegar.

Solve for M vinegar.

Answer 2

Sure! I can help you with that. To determine the molarity of acetic acid in vinegar, you need to use the concept of acid-base titration. Here's how you can calculate it step by step:

Step 1: Write the balanced chemical equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH):

CH3COOH + NaOH -> CH3COONa + H2O

Step 2: Determine the moles of NaOH used in the titration. You know the molarity of the NaOH solution is 0.613 M, and you used 33.75 mL of it. Convert the volume to liters by dividing by 1000:

Moles of NaOH = molarity × volume
= 0.613 mol/L × (33.75 mL / 1000 mL/L)
= 0.0207 mol

Step 3: Use the stoichiometry of the balanced equation to determine the moles of acetic acid:

According to the balanced equation, for every 1 mole of NaOH, there is 1 mole of acetic acid. Therefore, the moles of acetic acid in the vinegar are also 0.0207 mol.

Step 4: Calculate the molarity of acetic acid in the vinegar. The molarity is defined as moles of solute divided by the volume of the solution in liters:

Molarity = moles of solute / volume of solution (L)

Volume of solution = 25 mL / 1000 mL/L = 0.025 L

Molarity of acetic acid = 0.0207 mol / 0.025 L = 0.828 M

Therefore, the molarity of acetic acid in the vinegar is 0.828 M.

Remember to always double-check your calculations and make sure you follow the correct units in each step.