Nitrogen monoxide reacts with oxygen according to the equation below.. 2NO + O2 -----> 2NO2... How many moles of NO are required to produce 5.0 moles of NO2 in excess oxygen?

To determine the number of moles of NO required to produce 5.0 moles of NO2, you need to use the stoichiometric coefficients from the balanced equation.

The balanced equation is:
2NO + O2 -> 2NO2

The coefficient of NO in the balanced equation is 2, which means that 2 moles of NO are required to produce 2 moles of NO2.

So, if 2 moles of NO produce 2 moles of NO2, we can use that ratio to find the number of moles of NO required to produce 5.0 moles of NO2.

Since the ratio is 2 moles NO : 2 moles NO2, we can set up a simple proportion:
2 moles NO / 2 moles NO2 = x moles NO / 5.0 moles NO2

Now, cross-multiply and solve for x:
2 moles NO * 5.0 moles NO2 = 2 moles NO2 * x moles NO
10 moles NO2 = 2x moles NO
Divide both sides by 2:
x moles NO = 10 moles NO2 / 2
x moles NO = 5.0 moles NO

Therefore, 5.0 moles of NO are required to produce 5.0 moles of NO2 in excess oxygen.

Use the coefficients in the balanced equation to convert mols of one material to mols of any other material.