pls explain your answer
Which of the following solutions would be expected to be the best conductor of an electric current at room temperature?
a. 1.0 M CH3COOH
b. 0.10 M CH3COOH
c. 0.10 M CO(NH2)2
d. 0.10 M Na2SO4
e. 0.10 M NaCl
thanks
The one that produces the most ions. Which is that?
both c and d
Solutions
To determine which solution would be the best conductor of an electric current at room temperature, we need to consider the nature of the solute and its ability to dissociate into ions. A solution with more ions (charged particles) will conduct electricity better.
Let's analyze each option:
a. 1.0 M CH3COOH (acetic acid): Acetic acid is a weak acid, and it does not fully dissociate into ions in water. Therefore, it will not be a strong conductor of electricity.
b. 0.10 M CH3COOH: This concentration is lower than option a, so the conductivity would be even lower.
c. 0.10 M CO(NH2)2 (urea): Urea is a non-ionic compound, so it does not dissociate into ions in water. It will not conduct electricity.
d. 0.10 M Na2SO4 (sodium sulfate): Sodium sulfate is an ionic compound that dissociates into sodium (Na+) and sulfate (SO4^2-) ions in water. Therefore, it will be a good conductor of electricity.
e. 0.10 M NaCl (sodium chloride): Sodium chloride is also an ionic compound, and when dissolved in water, it dissociates into sodium (Na+) and chloride (Cl-) ions. Hence, it will be an excellent conductor of electricity.
Based on this analysis, options d (0.10 M Na2SO4) and e (0.10 M NaCl) would be expected to be the best conductors of electric current at room temperature.