An elephant herd started moving at a rate of 6 mph. One elephant stood still and was left behind. Then the stray elephant began running at a rate of 10 mph to reach the herd. The stray caught up in 5 minutes. How long (in hours) did the stray run to catch up? How far did it run?
If the stray ran 10mph for 5/60 min or 1/12 hr, then it ran 5/6 miles. We used distance = rate*time.
Find the distance that the herd traveled while the stray ran to catch up.
Ok, we know the stray ran 5/6 mi to catch them. The herd traveled 6mph * 1/12 hr or .5mi in that 5 min, so they traveled 5/6 mi - 3/6 mi = 2/6 or 1/3 mi before the stray started to run.
you made this question 5 days after i was born O_O
To find the time it took for the stray to catch up, we can use the formula distance = rate * time. We know that the stray ran at a rate of 10 mph for 5 minutes (or 5/60 hours), so the distance it ran is 10 * (5/60) = 5/6 miles.
Now let's find the distance that the herd traveled while the stray was running to catch up. We know that the herd was moving at a rate of 6 mph, so in the 5 minutes that the stray was running, the herd traveled 6 * (5/60) = 1/2 mile.
Since the stray ran a total of 5/6 miles and the herd only traveled 1/2 mile while the stray was running, the distance that the herd traveled before the stray started running to catch up is 5/6 - 1/2 = 1/3 mile.
To summarize:
- The stray ran for 5 minutes (or 5/60 hours) and covered a distance of 5/6 miles.
- The herd traveled a distance of 1/2 mile while the stray was running.
- Therefore, the distance that the herd traveled before the stray started running to catch up is 1/3 mile.