Can someone tell me if this is correct: Find the value of the polynomial -x^2-3x-1 when x=-4

-1(-4)^2+3(-4)-1
-1(8)+(12)-1
-8-12+1
-20+1
=19
Is this correct??

for x= -4

x^2 is not 8

x^2=(-4)^2=4^2=16

To find the value of the polynomial -x^2-3x-1 when x=-4, you can substitute the value of x into the polynomial expression and evaluate it.

Starting with the given polynomial expression: -x^2-3x-1

When x=-4, substitute -4 for every x in the expression:

-(-4)^2-3(-4)-1

Next, follow the order of operations (PEMDAS) to simplify:

-(-4)^2 gives -16 (since raising a negative number to an even power makes it positive: (-4)^2 = 16)

-3(-4) gives +12 (multiplying a negative number by a negative number gives a positive result)

Now you have:

-16 + 12 - 1

Simplify further:

-4 - 1 = -4

So, the value of the polynomial -x^2-3x-1 when x=-4 is -4.

To answer your question, no, your answer of 19 is not correct. The correct answer is -4.