The graph of y = f (x) = b^x, where b > 1, is translated such that the equation of

the new graph is expressed as
y – 2 = f (x – 1). The range of the new function is

A. y > 2
B. y > 3
C. y > –1
D. y > –2

the answer is B?? i am really confused in this question..help please!

thank u in advance

To solve this problem, we need to understand how the original graph y = b^x is being translated.

In the original graph, as b > 1, the function y = f(x) = b^x is an exponential function that increases rapidly as x increases. The base b determines how steep the graph is.

Now, let's consider the translation. The equation of the new graph is expressed as y - 2 = f(x - 1). This means that the graph of y = f(x) is shifted to the right by 1 unit and shifted up by 2 units.

The original graph had a range of y > 0 since the exponential function is always positive for positive x.

By shifting the graph up by 2 units, the range would now be y - 2 > 0, which simplifies to y > 2.

Therefore, the range of the new function is y > 2.

Hence, the correct answer is option A.