please could you help me to draw the structural formula of C_5 H_12
Is this right,
H H H H H
| | | | |
H – C – C – C – C – C – H
| | | | |
H H H H H
oppss it didn't come right.
This may or may not work, but you can try!
Try drawing it here -- http://www.scriblink.com/ -- using the various drawing and math and science tools across the top of the screen.
Then click on Get URL and then post that webaddress (URL) here, but put spaces between letters and dots in the URL so it'll post on Jiskha.
PS -- You should also click on Save!
Here is a link that shows n-pentane.
http://en.wikipedia.org/wiki/Pentane
You should be aware than there are two more isomers with the same formula of C5H12. One is isopentane and the other is neopentane. The hot link I gave you above is for the normal straight chain compound.
Thanks for the links! :) And using the first link I tired to draw the diagram. However I'm not able to post it here in this message! :( So what should I do?
Certainly! To draw the structural formula of a compound, such as C₅H₁₂, we need to determine the arrangement of its atoms and the types of bonds between them.
First, let's start with the carbon atoms. Since there are five carbon atoms (C₅), we'll need to arrange them in a straight chain or some other configuration, along with the hydrogen atoms to satisfy the valency of carbon (4) and hydrogen (1).
To determine the arrangement, we can follow some general guidelines:
1. Carbon atoms tend to form single bonds with other carbon atoms, resulting in a chain or branching structure.
2. Carbon atoms should have four bonds (either with other atoms or with other carbon atoms).
Since C₅H₁₂ has an excess of hydrogen atoms, it suggests that the carbon chain might be in the form of a straight chain with a few additional hydrogen atoms attached.
One possible structural formula for C₅H₁₂ is:
H H H H H
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H - C - C - C - C - C - C - H
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H H H H H
In this structure, each carbon atom has four bonds, with the remaining hydrogen atoms completing the valency requirements.
Please note that there can be multiple structural isomers for a given molecular formula, so this is just one possible arrangement.
I hope this helps! Let me know if you have any further questions.