a ray of light (f = 5.09 x 10^14 Hz) traveling in air strikes a block of sodium chloride at an angle of incidence of 30 degrees. What is the angle of refraction for the light ray in the sodium chloride?
19
Oh, sodium chloride, you salty dog! Let's dive into this optical escapade. Now, when light strikes a different medium, it kinda gets excited and changes direction. So, to figure out the angle of refraction for this ray of light, we can turn to Snell's Law. Snell Snails, it's time to get refractin'!
The equation goes like this: n₁(sinθ₁) = n₂(sinθ₂). Here, n₁ and n₂ are the indices of refraction, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.
Now, for sodium chloride, the approximate index of refraction is around 1.54. And since we have an angle of incidence of 30 degrees, we can go full math mode and calculate the angle of refraction.
Plugging in the values, we get: 1(sin30) = 1.54(sinθ₂). With a little algebra dance, we can solve for θ₂. Drumroll, please...
*drumroll*
The angle of refraction inside the sodium chloride is approximately 19.59 degrees! So, our light ray bends and dips, just like a banana in a salsa dip. Hope this answer lights up your day!
To find the angle of refraction for the light ray in sodium chloride, we can use Snell's Law. Snell's Law relates the angle of incidence and the angle of refraction to the indices of refraction of the two media involved.
Here are the steps to find the angle of refraction:
1. Find the indices of refraction for air and sodium chloride. The index of refraction of air is approximately 1.00 since it is very close to vacuum. The index of refraction for sodium chloride is 1.54.
2. Apply Snell's Law. Snell's Law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the indices of refraction of the two media:
n1 * sin(theta1) = n2 * sin(theta2)
Where:
n1 = index of refraction of the first medium (air)
theta1 = angle of incidence (given as 30 degrees)
n2 = index of refraction of the second medium (sodium chloride)
theta2 = angle of refraction (to be found)
Plugging the values into the equation, we get:
1.00 * sin(30 degrees) = 1.54 * sin(theta2)
3. Rearrange the equation to solve for theta2:
sin(theta2) = (1.00 * sin(30 degrees)) / 1.54
4. Calculate sin(theta2) using a calculator:
sin(theta2) ≈ 0.1945
5. Inverse the sine to find the angle of refraction:
theta2 = sin^(-1)(0.1945)
6. Calculate the angle theta2 (angle of refraction) using a calculator:
theta2 ≈ 11.23 degrees
So, the angle of refraction for the light ray in sodium chloride is approximately 11.23 degrees.
i nedd thw work
Google the refractive index of sodium chloride. Let the value be n. Then solve with the simple
n = sin i/sin r
The given frequency of speed of light in air is not useful.